Acceleration

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Categories: Physical quantity | Dynamics

Accelerate redirects here. For other uses, see Accelerate (disambiguation). For the forthcoming R.E.M. album, see Accelerate (R.E.M. album)

Image:Acceleration.svg

Acceleration is the rate of change of velocity. At any point on a speed-time graph, the magnitude of the acceleration is given by the slope of the tangent to the curve at that point.

In physics, acceleration is defined as the rate of change of velocity, or as the second derivative of position (with respect to time). It is then a vector quantity with dimension length/time². In SI units, acceleration is measured in meters/second² (m·s^-2). The term "acceleration" generally refers to the change in instantaneous velocity.

In common speech, the term acceleration is only used for an increase in speed; a decrease in speed is called deceleration. In physics, any increase or decrease in speed is referred to as acceleration and similarly, motion in a circle at constant speed is also an acceleration, since the direction component of the velocity is changing. See also Newton's Laws of Motion.

1 Relation to relativity
2 Formula
3 See also
4 External links

Relation to relativity

After completing his theory of special relativity, Albert Einstein realized that forces felt by objects undergoing constant proper acceleration are indistinguishable from those in a gravitational field. This was the basis for his development of general relativity, a relativistic theory of gravity. This is also the basis for the popular Twin paradox, which asks why one twin ages more rapidly when moving away from his sibling at near light-speed and then returning, since the aging twin can say that it is the other twin that was moving. General relativity solved the "why does only one object feel accelerated?" problem which had plagued philosophers and scientists since Newton's time (and caused Newton to endorse absolute space). In special relativity, only inertial frames of reference (non-accelerated frames) can be used and are equivalent; general relativity considers all frames, even accelerated ones, to be equivalent. (The path from these considerations to the full theory of general relativity is traced in the Introduction to general relativity.)

Formula

The formula for the average acceleration over a time period Failed to parse (Missing texvc executable; please see math/README to configure.): \Delta t

is

Failed to parse (Missing texvc executable; please see math/README to configure.): \mathbf{\bar{a}}=\frac{\mathbf{v}(t+\Delta t)-\mathbf{v}(t)}{\Delta t}

where

Failed to parse (Missing texvc executable; please see math/README to configure.): \mathbf{v}(t+\Delta t)

is the final velocity

Failed to parse (Missing texvc executable; please see math/README to configure.): \mathbf{v}(t)

is the initial velocity

Failed to parse (Missing texvc executable; please see math/README to configure.): t

is the initial time and Failed to parse (Missing texvc executable; please see math/README to configure.): \Delta t
is the change in time

The formula for the instantaneous acceleration at time Failed to parse (Missing texvc executable; please see math/README to configure.): t

is

Failed to parse (Missing texvc executable; please see math/README to configure.): \mathbf{a}(t)=\lim_{\Delta t \to 0}\frac{\mathbf{v}(t+\Delta t)-\mathbf{v}(t)}{\Delta t}=\frac{\mathrm{d}\mathbf{v}}{\mathrm{d}t}

Thus acceleration is the first derivative of velocity. One should note that the expression (Final position - Initial Position) / (Total time taken) is the average velocity, and the limit as the time interval approaches zero is the instantaneous velocity. Therefore, velocity is the first derivative of position, making acceleration the second.

One should also note that the average and instantaneous accelerations over a time period Failed to parse (Missing texvc executable; please see math/README to configure.): \Delta t=t_1-t_0

are related through the  Mean Value Theorem for Integrals:

Failed to parse (Missing texvc executable; please see math/README to configure.): \bar{\mathbf{a}}\int_{t_0}^{t_1}\mathrm{d}t=\int_{t_0}^{t_1}\mathbf{a}(t)\mathrm{d}t

Putting it all together means:

Failed to parse (Missing texvc executable; please see math/README to configure.): \mathbf{a} = \frac{\mathrm{d}\mathbf{v}}{\mathrm{d}t} = \frac{\mathrm{d}^2\mathbf{r}}{\mathrm{d}t^2}

where

Failed to parse (Missing texvc executable; please see math/README to configure.): \mathbf{a}