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Sine and cosine transforms

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Fourier sine transform

In mathematics, the Fourier sine transform is a special case of the continuous Fourier transform, arising naturally when attempting to transform an odd function. Consider the general Fourier transform:

Failed to parse (Missing texvc executable; please see math/README to configure.): F(\omega) = \mathcal{F}(f)(\omega) = \frac{1}{\sqrt{2\pi}} \int\limits_{-\infty}^\infty f(t) e^{-i\omega t}\,dt.


We may expand the integrand by means of Euler's formula:

Failed to parse (Missing texvc executable; please see math/README to configure.): F(\omega)=\frac{1}{\sqrt{2\pi}} \int\limits_{-\infty}^\infty f(t)(\cos\,{\omega t} - i\,\sin{ \,\omega t})\,dt,


or, written as the sum of two integrals:

Failed to parse (Missing texvc executable; please see math/README to configure.): F(\omega)=\frac{1}{\sqrt{2\pi}} \int\limits_{-\infty}^\infty f(t)\cos\,{\omega t} \,dt - \frac{i}{\sqrt{2\pi}} \int\limits_{-\infty}^\infty f(t)\sin\,{\omega t}\,dt.


Now notice that if we assume f(t) is an odd function, the product f(t)cosωt is also odd whilst the product f(t)sinωt is an even function. Since we are integrating over an interval symmetric about the origin (i.e. -∞ to +∞), the first integral must vanish to zero, and the second may be simplified to give:

Failed to parse (Missing texvc executable; please see math/README to configure.): F(\omega)= -i\,\sqrt{\frac{2}{\pi}} \int\limits_{0}^\infty f(t)\sin\,{\omega t} \,dt,


which is the Fourier sine transform for odd f(t). It is clear that the transformed function F(ω) is also an odd function, and a similar analysis of the general Inverse Fourier transform yields a second sine transform, namely:

Failed to parse (Missing texvc executable; please see math/README to configure.): f(t)= i\,\sqrt{\frac{2}{\pi}} \int\limits_{0}^\infty F(\omega)\sin\,{\omega t} \,d\omega.


Note that the numerical factors in the transforms are defined uniquely only by their product, as discussed for general continuous Fourier transforms. For this reason the imaginary units i and -i can be omitted, with the more commonly seen forms of the Fourier sine transforms being:

Failed to parse (Missing texvc executable; please see math/README to configure.): F(\omega)= \sqrt{\frac{2}{\pi}} \int\limits_{0}^\infty f(t)\sin\,{\omega t} \,dt,


and

Failed to parse (Missing texvc executable; please see math/README to configure.): f(t)= \sqrt{\frac{2}{\pi}} \int\limits_{0}^\infty F(\omega)\sin\,{\omega t} \,d\omega.


Fourier cosine transform

In mathematics, the Fourier cosine transform is a special case of the continuous Fourier transform, arising naturally when attempting to transform an even function. Consider the general Fourier transform:

Failed to parse (Missing texvc executable; please see math/README to configure.): F(\omega) = \mathcal{F}(f)(t) = \frac{1}{\sqrt{2\pi}} \int\limits_{-\infty}^\infty f(t) e^{-i\omega t}\,dt.


We may expand the integrand by means of Euler's formula:

Failed to parse (Missing texvc executable; please see math/README to configure.): F(\omega)=\frac{1}{\sqrt{2\pi}} \int\limits_{-\infty}^\infty f(t)(\cos\,{\omega t} - i\,\sin{ \,\omega t})\,dt,


or, written as the sum of two integrals:

Failed to parse (Missing texvc executable; please see math/README to configure.): F(\omega)=\frac{1}{\sqrt{2\pi}} \int\limits_{-\infty}^\infty f(t)\cos\,{\omega t} \,dt - \frac{i}{\sqrt{2\pi}} \int\limits_{-\infty}^\infty f(t)\sin\,{\omega t}\,dt.


Now notice that if we assume f(t) is an even function, the product f(t)cosωt is also even whilst the product f(t)sinωt is an odd function. Since we are integrating over an interval symmetric about the origin (i.e. -∞ to +∞), the second integral must vanish to zero, and the first may be simplified to give:

Failed to parse (Missing texvc executable; please see math/README to configure.): F(\omega)= \sqrt{\frac{2}{\pi}} \int\limits_{0}^\infty f(t)\cos\,{\omega t} \,dt,


which is the Fourier cosine transform for even f(t). It is clear that the transformed function F(ω) is also an even function, and a similar analysis of the general inverse Fourier transform yields a second cosine transform, namely:

Failed to parse (Missing texvc executable; please see math/README to configure.): f(t)= \sqrt{\frac{2}{\pi}} \int\limits_{0}^\infty F(\omega)\cos\,{\omega t} \,d\omega.


Note that the numerical factors in the transforms are defined uniquely only by their product, as discussed for general continuous Fourier transforms.


See also

References

  • Mary L. Boas, Mathematical Methods in the Physical Sciences, 2nd Ed, John Wiley & Sons Inc, 1983. ISBN 0-471-04409-1
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