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It is produced by decomposition of cubane (C₈H₈ → 2C₄H₄). As there is no strain on the bonds in this molecule (being 109°), tetrahedrane is much less volatile than cubane or, indeed, many other hydrocarbons.

According to [1]: "Tetrahedrane, however, is more strained than cubane and continues to defy preparation as an isolable compound, although derivatives of the basic structure have been made.." Which seems to contradict. Maximus Rex 05:10, 20 Jul 2004 (UTC)