Co-NP
From Wikipedia, the free encyclopedia
In computational complexity theory, co-NP is a complexity class. A problem Failed to parse (Missing texvc executable; please see math/README to configure.): \mathcal{X}
is a member of co-NP if and only if its complement Failed to parse (Missing texvc executable; please see math/README to configure.): \overline{\mathcal{X}} is in complexity class NP. In simple terms, co-NP is the class of problems for which efficiently verifiable proofs of no instances, sometimes called counterexamples, exist.
An example of an NP-complete problem is the subset sum problem: given a finite set of integers is there a non-empty subset which sums to zero? The complementary problem is in co-NP and asks: "given a finite set of integers, does every non-empty subset have a nonzero sum?" To give a proof of a "no" instance one must specify a non-empty subset which does sum to zero. This proof is then easy to verify.
P, the class of polynomial time solvable problems, is a subset of both NP and co-NP. P is thought to be a strict subset in both cases (and demonstrably cannot be strict in one case but not the other). NP and co-NP are also thought to be unequal. If so, then no NP-complete problem can be in co-NP and no co-NP-complete problem can be in NP.
This can be shown as follows. Assume that there is an NP-complete problem that is in co-NP. Since all problems in NP can be reduced to this problem it follows that for all problems in NP we can construct a non-deterministic Turing machine that decides the complement of the problem in polynomial time, i.e., NP is a subset of co-NP. From this it follows that the set of complements of the problems in NP is a subset of the set of complements of the problems in co-NP, i.e., co-NP is a subset of NP. Since we already knew that NP is a subset of co-NP it follows that they are the same. The proof for the fact that no co-NP-complete problem can be in NP is symmetrical.
If a problem can be shown to be in both NP and co-NP, that is generally accepted as strong evidence that the problem is probably not NP-complete (since otherwise NP = co-NP).
An example of a problem which is known to be in NP and in co-NP is integer factorization: given positive integers m and n determine if m has a factor less than n and greater than one. One direction is clear; if m does have such a factor then long division is a certificate. The other direction is slightly more subtle; one must list the prime factors of m and provide a primality certificate for each one.
Integer factorization is often confused with the closely related primality problem. Both primality testing and factorization have long been known to be NP and co-NP problems. The AKS primality test, published in 2002, proves that primality testing also lies in P, while factorization may or may not have a polynomial-time algorithm.[1]
References
- ^ Manindra Agrawal, Neeraj Kayal, Nitin Saxena, "PRIMES is in P", Annals of Mathematics 160 (2004), no. 2, pp. 781–793.
- Complexity Zoo: coNP
|
|
|---|
| P • NP • co-NP • NP-C • co-NP-C • NP-hard • UP • #P • #P-C • L • NL • NC • P-C • PSPACE • PSPACE-C • EXPTIME • NEXPTIME • EXPSPACE • 2-EXPTIME • PR • RE • Co-RE • RE-C • Co-RE-C • R • BQP • BPP • RP • ZPP • PCP • IP • PH |
